Enable assembler code only if it is known to work
on that operating system. I'm too lazy to think how to make a good Autoconf test for this and it's not that important anyway. No longer define HAVE_ASM_X86 or HAVE_ASM_X86_64. Inline assembler (if any) is used if a macro like __i386__ or __x86_64__ is defined.
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20
configure.ac
20
configure.ac
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@ -288,29 +288,27 @@ AC_ARG_ENABLE([assembler], AC_HELP_STRING([--disable-assembler],
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for the architecture.]),
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[], [enable_assembler=yes])
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if test "x$enable_assembler" = xyes; then
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enable_assembler=no
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case $host_os in
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# Darwin should work too but only if not creating universal
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# binaries. Solaris x86 could work too but I cannot test.
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linux* | *bsd* | mingw* | cygwin*)
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case $host_cpu in
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i?86) enable_assembler=x86 ;;
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x86_64) enable_assembler=x86_64 ;;
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*) enable_assembler=no ;;
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esac
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;;
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esac
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fi
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case $enable_assembler in
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x86)
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AC_DEFINE([HAVE_ASM_X86], [1],
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[Define to 1 if using x86 assembler optimizations.])
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;;
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x86_64)
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AC_DEFINE([HAVE_ASM_X86_64], [1],
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[Define to 1 if using x86_64 assembler optimizations.])
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;;
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no)
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x86 | x86_64 | no)
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AC_MSG_RESULT([$enable_assembler])
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;;
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*)
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AC_MSG_RESULT([])
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AC_MSG_ERROR([--enable-assembler accepts only \`yes', \`no', \`x86', or \`x86_64'.])
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;;
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esac
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AC_MSG_RESULT([$enable_assembler])
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AM_CONDITIONAL(COND_ASM_X86, test "x$enable_assembler" = xx86)
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AM_CONDITIONAL(COND_ASM_X86_64, test "x$enable_assembler" = xx86_64)
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